You roll a fair 6-sided die twice. Calculate the probability that the value of the first roll is strictly less than the value of the second roll.
Answer:
To solve the problem, we draw a grid showing outcomes of 2 dice rolls,
First Dice
Second Dice
1
2
3
4
5
6
1
X
X
X
X
X
X
2
✓
X
X
X
X
X
3
✓
✓
X
X
X
X
4
✓
✓
✓
X
X
X
5
✓
✓
✓
✓
X
X
6
✓
✓
✓
✓
✓
X
There are 36 possible outcomes when rolling two dice. The number of outcomes where the first dice is less than the second dice is 15. Therefore, the probability of the first dice being less than the second dice is 15/36.